Let Z={ x=(x);|;x>3} with the following operations: u+ v=uv-3(u+v)+12 k⋅ v =…

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Let Z={x=(x)    x>3} Z=\{\vec x=(x)\;|\;x>3\} with the following operations:
  • u+v=uv3(u+v)+12\vec u+\vec v=uv-3(u+v)+12
  • kv=(v3)a+3k\cdot \vec v = (v-3)^a+3
In this space the zero vector is: 0=4\vec 0 = 4

Find the additive inverse v-\vec v of v\vec v
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