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Sum & Difference Identities


The sum and difference identities, also known as Ptolemy's identities or compound formulas, are identities often used to evaluate non-special angles (i.e: π8\frac{\pi}{8}).

sin(α+β)=sinαcosβ+sinβcosαsin(αβ)=sinαcosβsinβcosαcos(α+β)=cosαcosβsinαsinβcos(αβ)=cosαcosβ+sinαsinβtan(α+β)=tanα+tanβ1tanαtanβtan(αβ)=tanαtanβ1+tanαtanβ\boxed{\begin{array}{rcl} \sin(\alpha+\beta)&=&\sin\alpha\cos\beta+\sin\beta\cos\alpha\\\\ \sin(\alpha-\beta)&=&\sin\alpha\cos\beta-\sin\beta\cos\alpha\\\\ \cos(\alpha+\beta)&=&\cos\alpha\cos\beta-\sin\alpha\sin\beta\\\\ \cos(\alpha-\beta)&=&\cos\alpha\cos\beta+\sin\alpha\sin\beta\\\\\\ \tan(\alpha+\beta)&=&\dfrac{\tan\alpha+\tan\beta}{1-\tan\alpha\tan\beta}\\\\ \tan(\alpha-\beta)&=&\dfrac{\tan\alpha-\tan\beta}{1+\tan\alpha\tan\beta} \end{array}}


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Example

Let's evalute cos(π12)\cos\Bigg(\dfrac{\pi}{12}\Bigg) using the sum and difference identities.

First, let's trying to express π12\dfrac{\pi}{12} as the sum or difference of two special angles.

π12=π3π4\dfrac{\pi}{12}=\dfrac{\pi}{3}-\dfrac{\pi}{4}


Therefore, cos(π12)=cos(π3π4)\cos\Bigg(\dfrac{\pi}{12}\Bigg)=\cos\Bigg(\dfrac{\pi}{3}-\dfrac{\pi}{4}\Bigg)


Then, using the difference identity for cosθ\cos\theta:

cos(αβ)=cosαcosβ+sinαsinβcos(π3π4)=cos(π3)cos(π4)+sin(π3)sin(π4)=(12)(12)+(32)(12)=1+322\begin{array}{rcl} \cos(\alpha-\beta)&=&\cos\alpha\cos\beta+\sin\alpha\sin\beta\\\\ \cos\Bigg(\dfrac{\pi}{3}-\dfrac{\pi}{4}\Bigg)&=&\cos\Bigg(\dfrac{\pi}{3}\Bigg)\cos\Bigg(\dfrac{\pi}{4}\Bigg)+\sin\Bigg(\dfrac{\pi}{3}\Bigg)\sin\Bigg(\dfrac{\pi}{4}\Bigg)\\\\ &=&\Bigg(\dfrac{1}{2}\Bigg)\Bigg(\dfrac{1}{\sqrt{2}}\Bigg)+\Bigg(\dfrac{\sqrt{3}}{2}\Bigg)\Bigg(\dfrac{1}{2}\Bigg)\\\\ &=&\boxed{\dfrac{1+\sqrt{3}}{2\sqrt{2}}} \end{array}
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Example: Sum & Difference Identities


Express 5π12\dfrac{5\pi}{12} as the sum or difference of two special angles.


Let 5π12=aπ12+bπ12\dfrac{5\pi}{12}=\dfrac{a\pi}{12}+\dfrac{b\pi}{12}, where a & ba~\&~b are integers that not relatively prime to 12 and that add to 5.


So, choose a=3a=3 and b=2b=2.

 5π12=3π12+2π12=π4+π6\begin{array}{rcl} \therefore~\dfrac{5\pi}{12}&=&\dfrac{3\pi}{12}+\dfrac{2\pi}{12}\\\\ &=&\dfrac{\pi}{4}+\dfrac{\pi}{6} \end{array}

Practice: Sum & Difference Identities


Find two special angles whose difference is 7π12\dfrac{7\pi}{12}.

Practice: Sum & Difference Identities

Evaluate cos(π12)\cos\Bigg(-\dfrac{\pi}{12}\Bigg). Leave answer in exact form.

Practice: Sum & Difference Identities


If sin(α+β)=sin(23π12)\sin(\alpha+\beta)=\sin\Bigg(\dfrac{23\pi}{12}\Bigg), then what is sin(αβ)?\sin(\alpha-\beta)?

Practice: Sum & Difference Identities

Using sum and difference identities, give the exact solution to tan(31π12)\tan\Bigg(\dfrac{31\pi}{12}\Bigg).

Practice: Sum & Difference Identities


Determine the exact value for sin(A+B)\sin(A+B) if cosA=513\cos{A}=\dfrac{5}{13} and sinB=45\sin{B}=\dfrac{4}{5}. Assume A & B\angle{A}~\&~\angle{B} are both in quadrant I.
Extra Practice