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The Ideal Gas Law

The equation below describes ideal gases. Real gases act differently, but act most similarly to ideal gases at high temperatures and low pressures!

PV=nRT\boxed{PV=nRT}

P is pressure measured in kPa (or maybe atm Torr, mmHg...)
V is volume measured in L or m3
n is number of moles of the gas
R is the ideal gas constant (will be either 8.314J/mol K OR 0.082 L atm/mol K)
T is temperature measured in K

Wize Tip
Pressure=Force/unit area=N/m2=1 Pa

How to convert different units of pressure:

101 300 Pa=101.3 kPa=1 bar=1 atm=760 mmHg=760 torr\boxed{101\ 300 \ Pa=101.3\ kPa=1 \ bar=1 \ atm=760 \ mmHg =760 \ torr}

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We mentioned that R (the ideal gas constant) could be either 8.314J/mol K or 0.082 L atm/mol K. How do we know which value to use?

Watch Out!
Using the correct value for R is more important than you might think! Students often make the mistake of using the wrong value of R on an exam and they get the question wrong. Let's see how we can easily prevent that :)


The ideal gas constant appears frequently in chemistry, for this reason, it comes in many forms depending on the context of its use and the units involved:
Example:

Suppose the variables in the ideal gas law equation had the following units:

P(kPa)×V(L)=n(mol)×R(?)×T(K)P(kPa)\times V(L)=n(mol)\times R(?)\times T(K)
What should R be in this case? (These terms need to combine correctly to ensure that this equation makes sense!)
R must be 8.314 J/ mol K which is the same as 8.314 kPa L/mol K



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Example: Ideal Gas Law

1.1 mols of Argon are stored in a 2.0 L container kept at 10.0 °C. What is the pressure of this gas? (ans. in kPa)

n=1.1, V=2L, T=10°C P=?
Is everything in correct units??

Need to convert T from °C to K °C + 273=K So 10°C + 273=283 K
PV=nRT
P=nRT/V
P=(1.1moles)(8.314kPa L/mol K)(283K)/2L
P=1294 kPa = 1300 kPa (sig figs)

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Example: Ideal Gas Law

a) A 4 L cylinder containing 3 moles of He(g) arrives from a chemical supply company. Given that the lab you are working in has a room temperature of 298 K, calculate the pressure inside the flask.

n=3 moln=3\ mol
V=4 LV = 4\ L
T=298 KT = 298\ K
PV=nRTPV=nRT
P=?P=?
P=nRTV=(3 mol)(0.08206 L atm K1mol1)(298 K)(4 L)=18.3 atmP=\dfrac{nRT}{V}=\dfrac{(3\ mol)(0.08206\ L\ atm\ K^{-1}mol^{-1})(298\ K)}{(4\ L)}=18.3\ atm

b) At what temperature will the cylinder have an internal pressure of 9 atm?

n=3 moln=3\ mol
V=4 LV=4\ L
P=9 atmP=9\ atm
T=?T=?
T=PVnR=(9 atm)(4 L)(3 mol)(0.08206 L atm K1mol1)=146 KT=\dfrac{PV}{nR}=\dfrac{(9\ atm)(4\ L)}{(3\ mol)(0.08206\ L\ atm\ K^{-1}mol^{-1})}=146\ K

c) Your lab mate steals some of the gas from your cylinder for a reaction he is doing. He fills a 1 L bulb with 1 atm of your gas at 298 K. If the cylinder is at room temperature, what is the internal pressure of the cylinder once the gas has been removed?


nstolen=PVRT=(1 atm)(1 L)(0.08206 L atm K1mol1)(298 K)=0.04 moln_{stolen}=\dfrac{PV}{RT}=\dfrac{(1\ atm)(1\ L)}{(0.08206\ L\ atm\ K^{-1}mol^{-1})(298\ K)}=0.04\ mol
Tank:
n=2.96 moln=2.96\ mol
T=298 KT=298\ K
V=4 LV=4\ L
P=nRTV=(2.96 mol)(0.08206 L atm K1mol1)(298K)(4 L)=18.1 atmP=\dfrac {nRT}{V}=\dfrac{(2.96\ mol)(0.08206\ L\ atm\ K^{-1} mol^{-1})(298K)}{(4\ L)}=18.1\ atm

Practice: Stoichiometry and the Ideal Gas Law

The combustion of methanol (CH3OH) is shown below. If 16 g of methanol is burned in oxygen, what volume of CO2 is produced if the pressure is 101.3 kPa, T = 25°C, and R = 8.314 kPa L/mol K? Round to the nearest whole number.

CH3OH + O2 → CO2 + H2O


Extra Practice