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Mass Percentage

Shows the amount that each element in a molecule contributes to the overall molecular mass.

Wize Tip
To determine the mass percentage for a particular element, follow these steps:

1) Find the atomic mass contribution of the element in question
2) Find the molar mass of the molecule
3) Solve for the mass percentage of an element using the equation below (take the mass contribution of an element and divide by the total molar mass, then multiply by 100)

mass percentage of element=mass controbution of elementtotal mass of molecule×100\boxed{\displaystyle \text{mass percentage of element} =\frac{\text{mass controbution of element}}{\text{total mass of molecule}}\times100}


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Example: What is the percentage of oxygen by mass in sodium hydroxide, NaOH?


mass percentage of O=mass controbution of oxygentotal mass of NaOH×100\displaystyle \text{mass percentage of O} =\frac{\text{mass controbution of oxygen}}{\text{total mass of NaOH}}\times100

1) Mass contribution of oxygen:
One oxygen atom so mO=1×15.999 g/mol=15.999 g/molm_O = 1 \times 15.999\ g/mol = 15.999\ g/mol

2) Total mass of NaOH:mNaOH=(1×MMNa)+(1×MMO)+(1×MMH)=22.990 g/mol+15.999 g/mol+1.008 g/mol=39.997 g/molm_{NaOH}=(1\times MM_{Na})+(1\times MM_O)+(1\times MM_H)=22.990\ g/mol+15.999\ g/mol+ 1.008\ g/mol=39.997\ g/mol


3) Find mass percentage of oxygen:

mass percentage=15.999 g/mol39.997 g/mol×100=40.00%\textrm{mass percentage}=\dfrac{15.999\ g/mol}{39.997\ g/mol}\times 100=40.00\%


Therefore, oxygen contributes to
40
% of the overall mass of NaOH!

Example: Mass Percentages of Elements in A Molecule


Sodium Bicarbonate (NaHCO3) is a very common chemical frequently used in the food industry. Find the mass percentages of each element in sodium bicarbonate.

Molar masses of each element:
  • Na is 22.99 g/mol
  • H is 1.01 g/mol
  • C is 12.01 g/mol
  • O is 16.00 g/mol

The molar mass of NaHCO3 is: 22.99 + 1.01 + 12.01 + 3(16) = 84.01 g/mol

The mass percentage of each element:

mass percentage of element=mass controbution of elementtotal mass of molecule×100\displaystyle \text{mass percentage of element} =\frac{\text{mass controbution of element}}{\text{total mass of molecule}}\times100

mass % Na = 22.99 / 84.01 x 100 = 27.36 %
mass % H = 1.01 / 84.01 x 100 = 1.20 %
mass % C = 12.01 / 84.01 x 100 = 14.30 %
mass % O = 48.00 / 84.01 x 100 = 57.14 %

Practice: Finding the Mass Percentage of Oxygen in Ethanol

What is the mass percentage of oxygen in ethanol (C2H5OH)?
Extra Practice