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VSEPR Theory


VSEPR aka Valence Shell Electron Pair Repulsion theory: states that repulsion of electron pairs (both bonds and lone pairs) in the valence shell will dictate the molecular geometry of a compound.


Wize Concept
To predict a molecular shape using VSEPR we need the BEST Lewis Structure!

Drawing the best Lewis Structure will provide us with two key pieces of information:
  • The number of lone pairs on the central atom
  • The number of bound atoms to the central atom
Once we have this information we can determine the electron geometry and the molecular shape as well as the bond angles of the molecule in question! These are all very common exam questions :)


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Electron Geometry (aka Orbital Geometry or Parent Shape)

Electron geometry is based on the number of electron groups around the central atom

EGs=number of lone pairs of electrons + number of bound atoms\boxed{EGs=\text{number of lone pairs of electrons + number of bound atoms}}
EGs are electron groups

Example:
How many electron groups does the C atom on the left have?


EGs=# of lone pairs of electrons + number of bound atoms
EGs=0 +2
EGs= 2

Watch Out!
The triple bond has no effect on EGs because we are counting the number of bound atoms, so whether there is a C bound to another C with a single bond, double bond, or triple bond, those will all just count as 1 EG!


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Molecular Shape

The shape of a molecule is determined by where the atoms are located.

Write the number of electron groups on the left side of the table.



Wize Tip
The tables in this lesson are very commonly tested on!
Take a few minutes to memorize these tables as you will likely see many questions relating to VSEPR theory on your exams!

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Write the number of electron groups on the left side of the table.


Note:

  • Wedges mean the bond is coming out of the page and dashes mean the bond is going back into the page.
  • LP=lone pairs of electrons
  • BA=bound atoms
  • Lone pairs give more push (are even more repelled by other electrons), which is why wee see the bond angles change slightly.

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Example: Parent and Molecular Shape

Determine the parent shape and molecular shape for the following.

a) NH3



Electron geometry: tetrahedral
Molecular shape: trigonal pyramidal

b) SCl2




Electron geomtery: tetrahedral
Molecular shape: bent

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c) IF7


Electron geometry: pentagonal bipyramidal
Molecular shape: pentagonal bipyramidal



d) SF4


Electron geometry: trigonal bipyramidal
Molecular shape: see-saw


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Example: VSEPR and Molly

MDMA (3,4-methylenedioxy-methamphetamine) or “Molly” is a psychoactive drug commonly used for recreational purposes, which has been investigated as a treatment for PTSD. It functions by triggering serotonin release and inhibiting serotonin reuptake in the human brain, causing euphoric and empathogenic effects on the user. The structure of MDMA is shown below.




a) What is the molecular shape of the nitrogen atom in MDMA?


Trigonal Pyramidal

b) Approximate the O-C-O bond angle in MDMA?


109.5109.5^\circ

c) How many atoms with a trigonal planar electron geometry are there in MDMA?


6


Practice: VSEPR Shapes

Consider the VSEPR for the “best” Lewis diagrams for the following species and use them to answer the next three questions

1. PH3

2. AlH4-

3. IO3-




Which of the following has a central atom with a tetrahedral electron-pair geometry?

Practice: Bond Angle Identification

Which of the following compounds has a 120o bond angle?

VSEPR and Molecular Shapes - Cheatsheet

The last shape when 7 atoms are bound to the central atom: pentagonal bipyramidal
Extra Practice