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Blackbody radiation


Classical Problem:


Issues:
  1. Classical Theory does not do a good job predict the emission of bodies in the infrared region, especially for cooler bodies.
  2. Near the UV-range classical theory predicts an infinite increase in radiance which means an infinite amount of light being emitted. This is a clear contradiction of energy conservation, a BIG ISSUE! Known as the UV-Catastrophe

Solution:
  1. Max Plank discovered that if the restricted energy that can be released or absorbed by atoms into discrete energy packets he could successfully predict the experimental observations.

Results:
  1. The smallest quantity of energy that can be emitted or absorbed as electromagnetic radiation, is called a quanta

The energy of a single quantum is:



E=hv=hcλE=hv=\frac{hc}{\lambda}
E = energy of the photon in Jh=6.626 x 1034Js (Planck’s Constant)ν=frequency in s1\begin{aligned} &\text{E = energy of the photon in J}\\&h = 6.626 \text{ x } 10^{-34}\text{Js (Planck's Constant)}\\&\nu = \text{frequency in s}^{-1} \end{aligned}


Wize Tip
You should memorize the value for the speed of light (c) = 3.0x108m/s as that value is not always provided on exams.


Wize Concept
Where will I see this on an exam?

Questions on this topic tend to arise in the form of a calculation. You will be asked to determine the energy or wavelength of a given ray of light.

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