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Cost, Revenue, and Profit

We can use our knowledge of calculus to solve many problems in economics.

Given the following:
  • xx, the number of items produced
  • C(x)C(x), the cost function, which represents the total cost of producing xx items
  • p(x)p(x), the price function, which represents the selling price for one item

Revenue

The revenue function R(x)R(x) represents the total revenue from the production of xx items, and is defined to be the number of items sold times the price of each:
R(x)=xp(x)\boxed{\quad R(x)=x\cdot p(x) \quad}

Profit

Then the profit function P(x)P(x) is defined to be the difference between revenue and cost of production:
P(x)=R(x)C(x)\boxed{\quad P(x)=R(x)-C(x) \quad}

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Average Change Functions

An average quantity is usually determined by taking all of the function values and dividing by how many we have. More specifically, an average function is constructed by diving the original function by xx, which represents the "number of items".

Average Cost is the cost function divided by xx: Cave=C(x)xC_{ \text{ave}}=\dfrac{C(x)}{x}

Average Revenue is the revenue function divided by xx: Rave=R(x)xR_{ \text{ave}}=\dfrac{R(x)}{x}

Average Profit is the profit function divided by xx: Pave=P(x)x P_{ \text{ave}}=\dfrac{P(x)}{x}

Marginal Functions

In business, a marginal quantity represents the instantaneous rate of change with respect to the number of items produced, xx

Marginal Cost is the derivative of the cost function: C(x)C'(x)

Marginal Revenue is the derivative of the revenue function:R(x)R'(x)

Marginal Profit is the derivative of the profit function: P(x)P'(x)
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Example: Marginal Cost

Suppose that a company’s total cost (in dollars) to carry out a production of xx units of its product is given by

C(x)=x2512+10x+100C(x)=\displaystyle\frac{x^{2}}{51^{2}}+10x+100

a) Find the average cost for the first 51 units produced.

b) Find the marginal cost for the first 5151 units produced.


Part a)

Average cost is defined: Cave=C(x)xC_{ \text{ave}}=\dfrac{C(x)}{x}


C(x)x=x2512+10x+100x=x512+10+100x\dfrac{C(x)}{x}=\dfrac{\displaystyle\frac{x^{2}}{51^{2}}+10x+100}{x}=\displaystyle \frac{x}{51^{2}}+10+\frac{100}{x}


Cave(51)=51512+10+10051C_{ \text{ave}}(51)=\displaystyle \frac{51}{51^{2}}+10+\frac{100}{51}


=151+10+10051=\dfrac{1}{51}+10+\dfrac{100}{51}

=6115111.98/item=\dfrac{611}{51}\approx11.98/\text{item}

Which is the average cost of producing all the items produced so far (all 51)

Part b)

Marginal cost = the derivative of the cost function.

Differentiate and evaluate at x=51x=51 :

C(x)=2x512+10C'(x)=\displaystyle\frac{2x}{51^{2}}+10

2512 (51)+10\Rightarrow \displaystyle\frac{2}{51^{2}}\ (51)+10

=251+10=\displaystyle\frac{2}{51}+10

=5125110.04/item=\displaystyle\frac{512}{51}\approx 10.04/\text{item}

Which is the cost for producing one item at this moment (after 5151 items have already been produced).

If the selling price of xx items is given by the function p(x)=502+xp(x)=\dfrac{50}{2+x} , what is the marginal revenue?





Given that the price of a commodity, in dollars, can be modeled as p(x)=12xp(x)=12-x , and the cost of production for one item can be modeled as: C(x)=x+1C(x)=x+1, find the following:

a) The marginal profit for the 3rd item sold

b) When should the company stop producing?



Extra Practice